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設f(x)=3x-7若g(x-1)=f(x+2)則g(-2)=?

A:

g(x-1)=g(-2), x=(-1) 帶回去,
=>f(x+2)=f(1). 帶回去,
=>f(x)=3x-7
=>f(1)=(-4)

Ans:(-4)

設f(x+3)=f(x)-3且f(3)=9,則f(12)=?

A:

依f(x)=ax+b, 得到:
a(x+3)+b=ax+b-3
=> a=(-1)
再由:f(3)=9 得到:
f(3)=3a+b=9
=>a代(-1) 得到b=12
=> 得到方程式: f(x)=(-1)x+12
則便可知道9f(12)=0*9=0

Ans:0

若 f(x)=-4x+9則f(x+3)=?

A:

f(x)=ax+b, f(x+c)=a(x+c)+b
就可知道題目之解:
f(x+3)=(-4)(x+3)+9=(-4)x-3

Ans:(-4)x-3

參考資料： Me, 國中生的見解.

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